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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2020
PhysicsEasysingle choice

An electron, a neutron and an alpha particle have same kinetic energy and their de-Broglie wavelength areλe, λnandλαrespectively. Which statement is correct about their de-Broglie wavelengths?

Options:

Answer:
A
Solution:

According to de-Broglie theory, the wavelength

λ=hp=h2mk

λ∝1m(for same kinetic energy)

The wavelength is inversely proportional to the root of mass of the particle.

Asme<mn<mα

So,λe>λn>λα

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves
⏱ 2mℹ️ Source: PYQ_2020

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