In a radioactive decay chain reaction, 90 230 Th nucleus decays into Po 84 214 nucleus. The ratio of the number of α to number of β - particles emitted in this process is _______.

Let number of α particles are n α and β particles are n β . Given: 90 Th 230 → 84 Po 214 + n α α + n β β . Change in mass number is = 230 - 214 = 4 n α ⇒ n α = 4 Number of proton, n β = 84 - 90 - 2 n a ⇒ n β = 2 So, the ratio, n α n β = 2

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PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2022

PhysicsEasynumerical

In a radioactive decay chain reaction, $_{90}^{230} Th$ nucleus decays into ${}_{84}^{214}{Po}$ nucleus. The ratio of the number of $α$ to number of $β^{-}$ particles emitted in this process is _______.

Answer:

2.00

Solution:

Let number of $α$ particles are $n_{α}$ and $β$ particles are $n_{β}$ .
Given: $_{90} {Th}^{230} \to_{84} {Po}^{214} + n_{α} α + n_{β} β$ .
Change in mass number is $= 230 - 214 = 4 n_{α}$
$\Rightarrow n_{α} = 4$
Number of proton, $n_{β} = 84 - (90 - 2 n_{a})$
$\Rightarrow n_{β} = 2$
So, the ratio, $\frac{n_{α}}{n_{β}} = 2$

Stream:JEE_ADVSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2022

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