A hydrogen atom in its ground state absorbs 10.2 e V of energy. The angular momentum of electron of the hydrogen atom will increase by the value of (Given, Planck's constant = 6.6 × 1 0 − 34 J s

Question

A hydrogen atom in its ground state absorbs 10.2 e V of energy. The angular momentum of electron of the hydrogen atom will increase by the value of (Given, Planck's constant = 6.6 × 1 0 − 34 J s ).

TestHub · Accepted Answer

Energy absorbed is given by, Δ E = 13.6 × ( n 1 2 ​ 1 ​ − n 2 2 ​ 1 ​ ) 10.2 = 13.6 × ( n 1 2 ​ 1 ​ − n 2 2 ​ 1 ​ ) Therefore, we get, n 1 ​ = 1& n 2 ​ = 2 The change in angular momentum Δ L = 2 π n 2 ​ h ​ − 2 π n 1 ​ h ​ = 2 π h ​ = 1.05 × 1 0 − 34 J s

Physics - Modern Physics Question with Solution | TestHub

Options:

Doubts & Discussion