Physics - Modern Physics Question with Solution | TestHub

$\left(t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}\right)x = \left(t_{mean}\right)y$

or$\frac{0·693}{{\lambda }_{\text{z}}}=\frac{1}{{\lambda }_{\text{y}}}$

Therefore,${\lambda }_x<{\lambda }_y=0.693 {\lambda }_y$

${\lambda }_x<{\lambda }_y$

or$Rate of decay = \lambda N$

Initially number of atoms$\left(N\right)$of both are equal but since${\lambda }_y>{\lambda }_x$, therefore,$y$will decay at a rate faster than$x$