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PhysicsModern PhysicsRadioactivityMedium2 minPYQ_2023

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The half life of a radioactive substance is $20$ minutes. In how much time, the activity of substance drops to $(\frac{1}{16}) t h$ of its initial value?NEET 2023 (All India)

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Answer:

Solution:

Activity of substance is given by, $A = \frac{A_{0}}{2^{n}}$ , where $n$ is the number of half-lives.
Now, $\frac{A_{0}}{16} = \frac{A_{0}}{2^{n}} \Rightarrow n = 4$
Therefore,
$n = \frac{t}{T_{\frac{1}{2}}} \Rightarrow t = 4 T_{\frac{1}{2}} = 4 \times 20 \min = 80 \min$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2023

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