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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2020

PhysicsEasysingle choice

An electron is accelerated from rest through a potential difference of $V$ volt. If the de Broglie wavelength of the electron is $1.227 \times 10^{- 2} nm$ , the potential difference is:NEET 2020 (Phase 1)

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Answer:

Solution:

$λ = 1.227 \times 10^{- 2} nm$

$= 0.1227 Å$

$λ = \frac{12.27}{\sqrt{v}} Å$

$0.227 = \frac{12.27}{\sqrt{v}} Å$

$\sqrt{v} = 10^{2} \Rightarrow v = 10^{4}$ volt

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2020

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