In the hydrogen atom, the electron is moving around the nucleus with velocity 2.18 × 10 6 m s - 1 in an orbit of radius 0.528 A ∘ . The acceleration of the electron is

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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

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In the hydrogen atom, the electron is moving around the nucleus with velocity $2.18 \times 10^{6} m s^{- 1}$ in an orbit of radius $0.528 \overset{\circ}{A}$ . The acceleration of the electron is

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Solution:

Given, $v = 2.18 \times 10^{6} {m s}^{- 1}, r = 0.528 \times 10^{- 10} m$

Acceleration of electron moving round the nucleus

$a =$ $\frac{{(2.18 \times 10^{6})}^{2}}{0.528 \times 10^{- 10}} \approx$ $9 \times 10^{22} m s^{- 2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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