Physics - Modern Physics Question with Solution | TestHub

Voltage,$V=400 V$

$\because$the de-Broglie wavelength of an electron

$\lambda =\frac{12.3}{\sqrt{V}} \stackrel{\circ }{\mathrm{A}}$

$=\frac{12.3}{\sqrt{400}} \stackrel{\circ }{\mathrm{A}}=\frac{12.3}{20} \stackrel{\circ }{\mathrm{A}}$

$=0.615 \stackrel{\circ }{\mathrm{A}}$

$\lambda =0.0615 \mathrm{n}\mathrm{m}$