Physics - Modern Physics Question with Solution | TestHub

A carbon nucleus has $6$ protons and $6$ neutrons. Total mass of carbon

             = $(6m_p = 6m_n)=12.099 \mathrm{amu}$

and $m_c =12.000 \mathrm{amu}$

mass defect $=\Delta \text{m}=0\text{.}099\text{ amu}$

$\frac{\text{Binding energy}}{\text{nucleons}}=\frac{\text{BE}}{\text{A}}=\frac{\left(\Delta \text{m}\right)931\text{.}4}{12}$

$=\frac{\left(0\text{.}099\right)\left(931\text{.}4\right)}{12}=7\text{.}68\text{MeV}$