Physics - Modern Physics Question with Solution | TestHub

Given, the difference in energy level$E = 2.3 \mathrm{eV}$

$= 2.3 \times 1.6 \times {10}^{-19} \mathrm{J}$

​Planck's constant$h = 6.63 \times {10}^{-34} \mathrm{J} \mathrm{s}$

Let$v$be the frequency, then$E = hf$

or$f=\frac{E}{h}=\frac{\text{2.3}\times \text{1.6}\times {\text{10}}^{-\text{19}}}{\text{6.63}\times {\text{10}}^{-\text{34}}}$

$= 5.6 \times {10}^{14} \mathrm{Hz}$