When a metallic surface is illuminated with monochromatic light of wavelength λ , the stopping potential is 5 V 0 . When the same surface is illuminated with light of wavelength 3 λ , the stopping pot

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When a metallic surface is illuminated with monochromatic light of wavelength λ , the stopping potential is 5 V 0 . When the same surface is illuminated with light of wavelength 3 λ , the stopping potential is V 0 . Then the work function of the metallic surface is

TestHub · Accepted Answer

5 e V 0 = h c λ - W ....(1) e V 0 - h c 3 λ - W ....(2) Solving equation (1) & (2) h c λ - W = 5 h c 3 λ - 5 W 4 W = 2 h c 3 λ ⇒ W = h c 6 λ

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