Physics - Modern Physics Question with Solution | TestHub

Total energy of electron $\mathrm{E}=-\frac{\mathrm{K}{\mathrm{Ze}}^2}{2\mathrm{r}}=\mathrm{K}.\mathrm{E}+\mathrm{P}.\mathrm{E}$ Potential energy in the orbit P.E $=\frac{-{\mathrm{KZe}}^2}{\mathrm{r}}$ $\therefore$ P.E. $=2\times \mathrm{E}\Rightarrow$ P.E. $=2\times (-13.6)=-27.2\mathrm{eV}$