Physics - Modern Physics Question with Solution | TestHub

Let the daughter nucleus be${}_Z{}^{A}X$. So, reaction can be shown as

${}_{92}{}^{238}\mathrm{U}\to {}_Z{}^{A}X+{}_2{}^4\mathrm{H}\mathrm{e}$

From conservation of atomic mass

$238= A+4$

$\Rightarrow A=234$

From conservation of atomic number

$92=Z+2$

$\Rightarrow Z=90$

So, the resultant nucleus$\mathrm{i}\mathrm{s} {}_{90}{}^{234} X , \mathrm{i.}\mathrm{e.}, {}_{90}{}^{234} \mathrm{T}\mathrm{h}.$