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PhysicsModern PhysicsAtomic structureEasy2 minQB

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The radius of electron's second stationary orbit in Bohr's atom is $R$ . The radius of $3^{r d}$ orbit will be

Answer:

Solution:

As we know, radius of hydrogen like atom $r \propto \frac{n ^{2}}{Z}$ .

Therefore,

$\frac{r _{2}}{r _{3}} = (\frac{n _{2}}{n _{3}})^{2}$

$\Rightarrow \frac{R}{r _{3}} = (\frac{2}{3})^{2}$

$\Rightarrow r_{3} = \frac{9}{4} R$

$= 2.25 R$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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