A nucleus of mass M + Δ m is at rest and decays into two daughter nuclei of equal mass 2 M each. Speed of light is C . The speed of daughter nuclei is

Conserving the momentum 0 = 2 M V 1 − 2 M V 2 V 1 = V 2 …… ( 1 ) Δ mc 2 = 2 1 ⋅ 2 M V 1 2 + 2 1 ⋅ 2 M ⋅ V 2 2 …… ( 2 ) Δ mc 2 = 2 M V 1 2 M 2Δ mc 2 = V 1 2 V 1 = c M 2Δ m

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PhysicsModern PhysicsNuclear physicsHard2 minPYQ_2010

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A nucleus of mass $M + Δ m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $C$ . The speed of daughter nuclei is

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Conserving the momentum $0 = \frac{M}{2} V_{1} - \frac{M}{2} V_{2} V_{1} = V_{2} \dots\dots (1) Δ mc^{2} = \frac{1}{2} \cdot \frac{M}{2} V_{1}^{2} + \frac{1}{2} \cdot \frac{M}{2} \cdot V_{2}^{2} \dots\dots (2) Δ mc^{2} = \frac{M}{2} V_{1}^{2} \frac{2Δ mc ^{2}}{M} = V_{1}^{2} V_{1} = c \frac{2Δ m}{M}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2010

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