Physics - Modern Physics Question with Solution | TestHub

$$ \nu $=\frac{\mathrm{c}}{\mathrm{\lambda }}=\mathrm{c}\mathrm{R}{\mathrm{Z}}^2\left(\frac{1}{{\mathrm{n}}_1^2}-\frac{1}{{\mathrm{n}}_2^2}\right)$

$\therefore \nu \propto Z^2$
For minimum frequency of radiation$\nu$, atomic number$\mathrm{Z}$should be minimum and it is 1 for both H and deuterium-atoms.

But from reduced mass effect,$\mathrm{R}$is smaller for H-atom and hence$\mathrm{v}$is minimum for H.