The ionization potential of hydrogen is 13.6 V. The energy required to remove an electron from the second orbit of hydrogen is:

Question

TestHub · Accepted Answer

The energy required to remove an electron from the $n$ th orbit of hydrogen is given by

$E_{n} = \frac{13.6}{n ^{2}}$ eV.

For the second orbit ( $n = 2$ ), the energy required is $E_{2} = \frac{13.6}{2 ^{2}} = \frac{13.6}{4} = 3.4$ eV.

Therefore, the energy required to remove an electron from the second orbit of hydrogen is 3.4 eV.

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