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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2020

PhysicsEasystatement

A particle is moving $5$ times as fast as an electron. The ratio of the de-Broglie wavelength of the particle to that of the electron is $1.878 \times 10^{- 4}$ . The mass of the particle is close to :

Options:

Answer:

Solution:

$λ = \frac{h}{mv}$
$\Rightarrow \frac{m^{'}}{m} = \frac{v λ}{v^{'} λ^{'}} = \frac{1}{5} \times \frac{1}{1.878} \times 10^{- 4} \times 9.1 \times 10^{- 31}$
$m^{'} = 9.7 \times 10^{- 28} kg$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2020

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