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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

In Uranium $(Z = 92)$ , the $K$ absorption edge is $0 .107 Å$ and the $K_{α}$ line is $0 .126 Å$ . The wavelength of the $L$ absorption edge is

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Answer:

Solution:

Energy of K absorption edge is

$E (K) = \frac{h c}{λ_{K}} = \frac{12.4}{0.107} = 115.9 k e V$ ,

Energy of Kα line is

$E (K_{a}) = E (K) - E (L) = \frac{h c}{λ_{a}} = \frac{12.4}{0.126} = 98.4 k e V$

Therefore energy of L absorption edge is

L $E_{L} = (E_{K}) - E (K_{a}) = 115.9 - 98.4$

L $E_{L} = 17.5 k e V$

The wavelength of the L absorption edge is

$λ_{L} = \frac{h c}{E_{L}} = \frac{12.4 k e V Å}{17.5 k e V} = 0.709 Å$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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