Starting with a sample of pure 66 Cu , 7 8 of it decays into Zn in 15 minutes. The corresponding half-life is

N N 0 = 1 2 t / T ∴ 1 8 = 1 2 15 / T ⇒ 1 2 3 = 1 2 15 / T ∴ 15 T = 3 ⇒ T = 5 min .

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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020

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Starting with a sample of pure $^{66} Cu$ , $\frac{7}{8}$ of it decays into $Zn$ in $15$ minutes. The corresponding half-life is

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Solution:

$\frac{N}{N_{0}} = {(\frac{1}{2})}^{t / T}$

$∴$ $\frac{1}{8} = {(\frac{1}{2})}^{15 / T} \Rightarrow {(\frac{1}{2})}^{3} = {(\frac{1}{2})}^{15 / T}$

$∴$ $\frac{15}{T} = 3 \Rightarrow T = 5 min$ .

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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