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PhysicsModern PhysicsNuclear physicsEasy2 minPYQ_2022

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In the following nuclear reaction,
$D \overset{α}{\to} D_{1} \overset{β^{-}}{\to} D_{2} \overset{α}{\to} D_{3} \overset{γ}{\to} D_{4}$
Mass number of $D$ is $182$ and atomic number is $74$ . Mass number and atomic number of $D_{4}$ respectively will be

Options:

Answer:

Solution:

Equivalent reaction can be written as $D \to D_{4} + 2 α + β^{-} + γ$

So, mass number of $D_{4} =$ mass number of $D - 2 \times 4 = 182 - 8 = 174$

Atomic number of $D_{4} =$ atomic number of $D - 2 \times 2 + 1 = 74 - 4 + 1 = 71$

The reaction is

${}_{74}^{182}D \underset{α}{⟶} {}_{72}^{178}D_{1} \underset{β^{-}}{⟶} {}_{73}^{178}D_{2} \underset{α}{⟶} {}_{71}^{174}D_{3} \underset{γ}{\to} {}_{71}^{174}D_{4}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2022

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