The ratio of radii of nuclei Al 27 13 and X A 52 is 3 : 5. The number of neutrons in the nuclei of X will be

r ∝ A 1 3 ⇒ 3 5 = 27 A 1 3 A = 125 N n = A - Z = 125 - 52 = 73

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PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020

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The ratio of radii of nuclei ${}_{13}{Al}^{27}$ and ${}_{52}X^{A}$ is 3 : 5. The number of neutrons in the nuclei of $X$ will be

Answer:

Solution:

$r \propto A^{\frac{1}{3}}$

$\Rightarrow \frac{3}{5} = {(\frac{27}{A})}^{\frac{1}{3}}$

$A = 125$

$N_{n} = A - Z = 125 - 52 = 73$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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