The magnetic field associated with a light wave is given, at the origin, by B = B 0 sin ⁡ 3.14 × 10 7 c t + sin ⁡ 6.28 × 10 7 c t . If this light falls on a silver plate having a work function of 4 .7

Question

The magnetic field associated with a light wave is given, at the origin, by $B = B_{0} [\sin (3.14 \times 10^{7}) c t + \sin (6.28 \times 10^{7}) c t] .$ If this light falls on a silver plate having a work function of $4 .7 eV,$ what will be the maximum kinetic energy of the photoelectrons?

$(c = 3 \times 10^{8} m s^{- 1}, h = 6 .6 \times 10^{- 34} J s)$

TestHub · Accepted Answer

B = B 0 sin ⁡ 3.14 × 10 7 c t + sin ⁡ 6.28 × 10 7 c t Maximum K E will associate with the maximum frequency f max ⁡ = 6.28 × 10 7 c 2 π = 10 7 × 3 × 10 8 Hz = 3 × 10 15 Hz K E m a x = h f m a x - ϕ = 6 .63 × 10 - 34 × 3 × 10 15 1 .6 × 10 - 19 - 4 .7 eV = 7 .72 eV

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