Physics - Modern Physics Question with Solution | TestHub

A photo-emissive substance is illuminated with a radiation of wavelength ${\lambda }_i$ so that it releases electrons with de-Broglie wavelength ${\lambda }_e$. The longest wavelength of radiation that can emit photoelectron is ${\lambda }_0$. Expression for de-Broglie wavelength is given by :
( $\mathrm{m}:$ mass of the electron, $\mathrm{h}:$ Planck's constant and $c$ : speed of light)