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PhysicsModern PhysicsNuclear physicsMedium2 minPYQ_2010

PhysicsMediumsingle choice

The mass of a $_{3} Li^{7}$ nucleus is $0.042 u$ less than the sum of the masses of all its nucleons. The binding energy per nucleon of $_{3} Li^{7}$ nucleus is nearlyNEET 2010 (Screening)

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Solution:

If $m = 1 u, c = 3 \times 1 0^{8} ms^{- 1}$ , then $E = 931 MeV$ ie, $1 u = 931 MeV$ Binding energy $= 0.042 \times 931 = 39.10 MeV$ $∴$ Binding energy per nucleon $= \frac{39.10}{7} = 5.58 \approx 5.6 MeV$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2010

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