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PhysicsModern PhysicsDe Broglie & Matter WavesHard2 minPYQ_2013

PhysicsHardsingle choice

The wavelength $λ_{e}$ of an electron and $λ_{p}$ of a photon of same energy $E$ are related byNEET 2013 (All India)

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Solution:

Wavelength of electron, $λ_{e} = \frac{h}{2 m E} and proton λ_{p} = \frac{h c}{E} \Rightarrow λ_{e}^{2} = \frac{h ^{2}}{2 m E} or E = \frac{h c}{λ _{p}} ∴ λ_{e}^{2} = \frac{h ^{2}}{2 m \cdot \frac{h c}{λ _{p}}} \Rightarrow λ_{e}^{2} = \frac{h ^{2}}{2 mh C} λ_{p} \Rightarrow λ_{e}^{2} \propto λ_{p}$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2013

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