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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

The radius of hydrogen atom in its ground state is $5.3 \times 10^{- 11} m$ . After collision with an electron it is found to have a radius of $21.2 \times 10^{- 11} m$ . What is the principal quantum number $n$ of the final state of the atom?

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Answer:

Solution:

$r \propto n^{2}$

$\frac{r_{f}}{r_{i}} = {(\frac{n_{f}}{n_{i}})}^{2}$

$\frac{21.2 \times 10^{- 11}}{5.3 \times 10^{- 11}}$ = ${(\frac{n}{1})}^{2}$

$n^{2} = 4$

$n = 2$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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