Physics - Modern Physics Question with Solution | TestHub

Energy of photon $E=1\mathrm{MeV}$ Momentum of photon $P=\frac{E}{C}$ $$\begin{array}{rl}P& =\frac{E}{C}=\frac{1\times 10^6\times 1.6\times 10^{-19}}{3\times 10^8}\\ & =5\times 10^{-22}\mathrm{kg}\mathrm{m}/\mathrm{s}\end{array}$$