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PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2020
PhysicsEasysingle choice

Distance in free space at which intensity of5 eVneutron beam reduces to half will be nearly: (Take half-life of the neutron=12.8 min)

Options:

Answer:
D
Solution:

The kinetic energy of the neutron beam5 eV=12 mv2

121.67×10-27v2=5×1.6×10-19

⇒v=31 km s-1

distance travelled in one half-lifed=vt=31×103×12.8×60 m≃24000 km 

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity
⏱ 2mℹ️ Source: PYQ_2020

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