Physics - Modern Physics Question with Solution | TestHub

If the momentum of $\alpha$ and $\beta$ particles are $p$, if this is also equal to $hv/c$ of the photon - $\gamma$-rays, ${\lambda }_{\text{de Broglie }}=h/p$ As $p$ is the same, the wavelength will be the same. For $\alpha$ and $\beta$ particles, they are de Broglie waves and in the case of photons ( $\gamma$-rays), it is the wavelength of the associated electromagnetic wave.