Physics - Modern Physics Question with Solution | TestHub

Nuclear stability depends upon the ratio of neutron to proton. If the $n/p$ ratio is more than the critical value, then a neutron gets converted into a proton forming a ${\beta }^{-}$particle in the process. $$n\to p+e^{-}$$ The ${\beta }^{-}$particle ( $e^{-})$is emitted from the nucleus in some radioactive transformation. So electrons do not exist in the nucleus but they result in some nuclear transformation.