Photons with energy of 5 eV are incident on a cathode, C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C , no photoelectron

Question

Photons with energy of 5 eV are incident on a cathode, C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C , no photoelectrons will reach the anode, A , if, the stopping potential of A relative to C isNEET 2016 (Phase 2)

TestHub · Accepted Answer

E max = E - ϕ 2 e V = 5 e V - ϕ ⇒ ϕ = 3 e V . Now, eV 0 = E - ϕ = 6 e V - 3 e V = 3 e V . So, the stopping potential is - 3 V .

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