In hydrogen atom, electron excites from ground state to higher energy state and its orbital velocity is reduced to 3 1 rd of its initial value. The radius of the orbit in the ground state is R. The radius of the orbit in that higher energy state is :

v ∝ n 1 v 1 v n = 3 1 ⇒ n = 3 r ∝ n 2 r 3 = 9 R Option (D)

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PhysicsModern PhysicsAtomic structureMedium2 minQB

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In hydrogen atom, electron excites from ground state to higher energy state and its orbital velocity is reduced to $\frac{1}{3} rd$ of its initial value. The radius of the orbit in the ground state is R. The radius of the orbit in that higher energy state is :

Options:

Answer:

Solution:

$v \propto \frac{1}{n}$

$\frac{v _{n}}{v _{1}} = \frac{1}{3} \Rightarrow n = 3$

$r \propto n^{2}$

$r_{3} = 9 R$

Option (D)

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

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