Physics - Magnetism Question with Solution | TestHub

Let $r_1$ and $r_2$ be the radius of coil 1 and coil 2 . If $B_1$ and $B_2$ are magnetic induction at their centre then $B_1=\frac{{\mu }_0{I}_1}{2r_1}$ and $B_2=\frac{{\mu }_0{I}_2}{2r_2}$ $B_1=B_2$ and $r_1=2r_2$ there $I_1=2I_2$ Again if $R_1$ and $R_2$ are resistance of the coil 2 then $R_1=2R_2$ (as $R\propto$ length $=2\pi r)$ and if $v_1$ and $v_2$ are the potential difference across them respectively then $$\begin{array}{rl}\frac{V_1}{V_2}& =\frac{I_1{R}_1}{I_2{R}_2}\\ & =\frac{\left(2I_2\right)\left(2R_2\right)}{I_2{R}_2}=4\end{array}$$