Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2020
PhysicsEasysingle choice

A charged particle having a mass of1.6×10–26 kgcomes out of accelerator tube with kinetic energy2×103 eV. Calculate the smallest magnitude of the magnetic field that should be applied in vertically downwards direction to just prevent the charged particle from colliding the plate (Assume charge on particle = charge of the proton)

Options:

Answer:
A
Solution:

r=d⇒2mkqB=d     ⇒B=2mkq2d2

⇒B=2×1.6×10–26×2×103×ee2×10–4

⇒B=2×1.6×10–26×2×1031.6×10–19×10–4=2 T

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force
⏱ 2mℹ️ Source: PYQ_2020

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