A triangular shaped wire carrying 10 A current is placed in a uniform magnetic field of 0 . 5 T , as shown in figure. The magnetic force on segment C D is (Given B C = C D = B D = 5 cm ).

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TestHub · Accepted Answer

Force due to magnetic field on a current carrying conductor is given by, $\vec{F} = i \vec{l} \times \vec{B}$ .
The angle between the magnetic field and the direction of the current in the wire $C D$ is $60 °$ . Therefore,
$F = i l B \sin 60 ° \Rightarrow F = 10 \times 0.05 \times 0.5 \times \frac{\sqrt{3}}{2} \Rightarrow F = 0.216 N$

Physics - Magnetism Question with Solution | TestHub

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