A current carrying closed loop in the form of a right angle isosceles triangle $A BC$ is placed in a uniform magnetic field acting along $A B$ . If the magnetic force on the $arm BC$ is $F$ , the force on the arm $A C$ is
NEET 2011 (Screening)

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Answer:

A

Solution:

$F_{A B} = 0 F_{A B} + F_{BC} + F_{C A} = 0 F_{BC} + F_{C A} = 0 F_{C A} = - F_{BC} = - F$

TestHub · Accepted Answer

F A B ​ = 0 F A B ​ + F BC ​ + F C A ​ = 0 F BC ​ + F C A ​ = 0 F C A ​ = − F BC ​ = − F ​

Physics - Magnetism Question with Solution | TestHub

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