Physics - Magnetism Question with Solution | TestHub

The magnetic field inside the solenoid is given by

$\mathrm{B}={\mathrm{\mu }}_0\mathrm{n}{\mathrm{i}}_0$

(n = Number of turns per unit length, I = Current in coil)

Where$\mathrm{n}=\frac{\mathrm{N}}{\mathrm{L}}.\mathrm{r}$

$\mathrm{n}=\frac{500}{0.4\times {10}^{-2}}\times 1\times {10}^{-2}$

$\mathrm{n}=1000$

${\mathrm{\mu }}_0=4\mathrm{\pi }\times {10}^{-7}\mathrm{ }\mathrm{T}\mathrm{m}/\mathrm{A}$

$\mathrm{B}=4\times 3.14\times 1000\times 5\times {10}^{-7}$

$=62800\times {10}^{-7}$

$=6.28\times {10}^{-3}\mathrm{ }\mathrm{T}$