Physics - Magnetism Question with Solution | TestHub

${\text{B}}_1=\frac{2{\mu }_0}{4\pi }\frac{\text{M}}{{\text{r}}^3}$(As the dipole is short)

$=\frac{10^{-7}\times 1\times 2}{{\left(1\right)}^3}=2\times 10^{-7}T$



${\text{B}}_2=\frac{{\mu }_0}{4\pi }\frac{\text{M}}{{\text{r}}^3}=10^{-7}T$

${\text{B}}_{\text{net}}=\sqrt{5}\times 10^{-7}T$