Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2020
PhysicsEasysingle choice

A particle of charge-16×10-18 Cmoving with velocity10 m s-1along thex-axis enters a region where a magnetic field of inductionBis along they-axis and an electric field of magnitude104 V m-1is along the negativez-axis. If the charged particle continues moving along thex-axis, the magnitude ofBis

Options:

Answer:
A
Solution:

The force on a particle is

F=qE+v×B

orF=Fe+Fm

Fe=qE

 =-16×10-18×104-k^

=16×10-14k^

andFm=-16×10-18(10i^×Bj^)

=-16×10-17×B(+k^)

=-16×10-17B×k^

Since particle will continue to move along +x-axis, so resultant force is equal to0.

Fe+Fm=0

∴    16×10-14=16×10-17B
⇒    B=16×10-14 16×10-17=103

B=103 Wbm-2

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force
⏱ 2mℹ️ Source: PYQ_2020

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