In a uniform magnetic field, the magnetic needle has a magnetic moment 9 . 85 × 10 - 2 A m - 2 and moment of inertia 5 × 10 - 6 kg m 2 . If it performs 10 complete oscillations in 5 seconds then the m

Question

In a uniform magnetic field, the magnetic needle has a magnetic moment $9.85 \times 10^{- 2} A m^{- 2}$ and moment of inertia $5 \times 10^{- 6} kg m^{2} .$ If it performs $10$ complete oscillations in $5$ seconds then the magnitude of the magnetic field is ____ $mT$ [Take $π^{2}$ as $9.85]$

Answer:

8

Solution:

$T = 2 π \sqrt{\frac{I}{M B}}$
$B = 80 \times 10^{- 4} = 8 mT$

TestHub · Accepted Answer

T = 2 π I M B B = 80 × 10 - 4 = 8 mT

Physics - Magnetism Question with Solution | TestHub

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