Physics - Magnetism Question with Solution | TestHub

Given, angle of dip$\delta =22^{\text{o}}$

Horizontal component of the earth's magnetic field$\text{H = 0}\text{.35 G}$

Let the magnitude of the earth's magnetic field at the place is$\text{R}$.

Using the formula,$H=\text{R }\text{cos }\delta$

or$\text{R}=\frac{\text{H}}{\text{cos }\delta }=\frac{0\text{.}35}{\text{cos }22^{\text{o}}}=\frac{0\text{.}35}{0\text{.}9272}=0\text{.}3\mathrm{8 }\text{G}$

Thus, the value of the earth's magnetic field at that place is$\text{0}\text{.38 G}$.