Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldMedium2 minPYQ_2020

PhysicsMediumsingle choice

A particle of specific charge $\frac{q}{m} = π C {kg}^{- 1}$ is projected from the origin towards positive x-axis with a velocity of $10 m s^{- 1}$ in a uniform magnetic field $\vec{B} = - 2 \hat{k} T$ . The velocity $\vec{v}$ of the particle after time $t = \frac{1}{12} s$ will be (in $m s^{- 1}$ )

Options:

Answer:

Solution:

Time period, $T = \frac{2 π m}{qB} = \frac{2 π}{π \times 2} = 1 s$

Thus, the particle will be at point P after $t = \frac{1}{12} s$

$\vec{v} = 10 [cos 30 \hat{i} + sin 30 \hat{j}]$

$\vec{v} = 10 [\frac{\sqrt{3}}{2} \hat{i} + \frac{1}{2} \hat{j}] = 5 [\sqrt{3} \hat{i} + \hat{j}] {m s}^{- 1}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...