Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2024

PhysicsEasynumerical

A charge of $4.0 μ C$ is moving with a velocity of $4.0 \times 10^{6} m s^{- 1}$ along the positive $y$ -axis under a magnetic field $B$ of strength $(2 \hat{k}) T$ . The force acting on the charge is $x \hat{i} N$ . The value of $x$ is ______.

Answer:

32.00

Solution:

Given:

$q = 4 μ C, \vec{v} = 4 \times 10^{6} \hat{j} m s^{- 1}$ and $\vec{B} = 2 \hat{k} T$

Force acting on charged particle, $\vec{F} = q (\vec{v} \times \vec{B})$

$= 4 \times 10^{- 6} (4 \times 10^{6} \hat{j} \times 2 \hat{k})$

$= 4 \times 10^{- 6} \times 8 \times 10^{6} \hat{i}$

$\Rightarrow \vec{F} = 32 \hat{i} N$

$\Rightarrow x = 32$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2024

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