Physics - Magnetism Question with Solution | TestHub

Let$\theta =dip angle$

$B_H=$Horizontal component of magnetic field of earth

$B_V=$Vertical component of magnetic field of earth

Also,$\tan \theta =\left(\frac{B_v}{B_H}\right)$

But$\tan {45}^o=\frac{B_V}{B_H\cos {30}^o}$

$\therefore \frac{\tan \theta }{\tan {45}^o}=\cos {30}^o$

$\theta ={\tan }^{-1}\left(\frac{\sqrt{3}}{2}\right)$