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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

A charged particle enters a uniform magnetic field with a velocity vector at an angle of $45 °$ with the magnetic field. The pitch of the helical path followed by the particle is $p$ . The radius of the helix will be

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Answer:

Solution:

Pitch of helical path is

$p = (v \cos θ) \times \frac{2 π m}{q B}$

$\Rightarrow p = \frac{2 π m v \cos 45 °}{q B}$

$\Rightarrow p = \frac{2 π m v}{\sqrt{2} q B}$

Also radius of helix is,

$r = \frac{m v \sin θ}{q B}$

$\Rightarrow r = \frac{m v}{\sqrt{2} q B}$

$∴ \frac{r}{p} = \frac{m v}{\sqrt{2} q B} \times \frac{\sqrt{2} q B}{2 π m v}$

$\frac{r}{p} = \frac{1}{2 π}$

or $r = \frac{p}{2 π}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2020

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