Physics - Magnetism Question with Solution | TestHub

Given,$l=5cm=5\times {10}^{-2}m,$
$a=2c{m}^2=2\times {10}^{-4}{m}^2$
And$M=1A{m}^{-2}$
The magnetisation of the bar magnet is given by
$l=\frac{M}{V}$
where, V = volume of bar magnet =$a\times l$
$\Rightarrow l=\frac{M}{a\times l}$
Substituting given values, we get
$l=\frac{1}{2\times {10}^{-4}\times 5\times {10}^{-2}}=\frac{1}{{10}^{-5}}$
$=1\times \frac{{10}^{5}A}{m}$