For a moving coil galvanometer, the deflection in the coil is 0 . 05 rad when a current of 10 mA is passed through it. If the torsional constant of suspension wire is 4 . 0 × 10 – 5 N m rad - 1 , the

Question

For a moving coil galvanometer, the deflection in the coil is 0 . 05 rad when a current of 10 mA is passed through it. If the torsional constant of suspension wire is 4 . 0 × 10 – 5 N m rad - 1 , the magnetic field is 0 . 01 T and the number of turns in the coil is 200 , the area of each turn (in cm 2 ) is :

TestHub · Accepted Answer

Given: θ = 0 . 05 rad , I = 10 mA , K = 4 × 10 - 5 N m rad - 1 , B = 0 . 01 T , N = 200 The torsional constant of a wire used in a moving coil galvanometer is given by K = N I A B θ , where, A is area of each turn So, A = K θ N I B = 4 × 10 - 5 × 0 . 05 200 × 10 × 10 - 3 × 0 . 01 Thus, A = 10 - 4 m 2 = 1 cm 2

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