An electron is moving with initial velocity v = a k ^ in a magnetic field B = b j ^ . Its de-Broglie wavelength will

Question

An electron is moving with initial velocity v = a k ^ in a magnetic field B = b j ^ ​ . Its de-Broglie wavelength will

TestHub · Accepted Answer

The magnetic force on a moving charge is given by $F = q (v \times B)$ .

Since the magnetic force is always perpendicular to the velocity of the particle, the work done by the magnetic field is zero.

According to the work-energy theorem, the kinetic energy and the speed $v$ of the electron remain constant.

The de-Broglie wavelength is given by $λ = \frac{h}{m v}$ .

Since the speed $v$ remains constant, the de-Broglie wavelength $λ$ remains constant.

Answer: remain constant.

Physics - Magnetism Question with Solution | TestHub

Options:

Doubts & Discussion