Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2019

PhysicsEasysingle choice

A particle having the same charge as of electron moves in a circular path of radius $0.5 c m$ under the influence of a magnetic field of $0.5 T .$ If an electric field of100 V/mmakes it to move in a straight path, then the mass of the particle is (Given charge of electron $= 1.6 \times 10^{- 19} C$ )

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Answer:

Solution:

Force to due to magnetic field

$F = e v B = \frac{m v^{2}}{R}$

with electric field also, net force is zero.

$∴ e E = e v B$

$\Rightarrow E = v B$

$E = \frac{e B R}{m} . B$

$\Rightarrow m = \frac{e B^{2} R}{E} = \frac{1.6 \times 10^{- 19} \times {(0.5)}^{2} . (0.5 \times 10^{- 2})}{100} k g$

$= 2.0 \times 10^{- 24} k g$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2019

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